5x^2-17x+40=0

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Solution for 5x^2-17x+40=0 equation:


Simplifying
5x2 + -17x + 40 = 0

Reorder the terms:
40 + -17x + 5x2 = 0

Solving
40 + -17x + 5x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
8 + -3.4x + x2 = 0

Move the constant term to the right:

Add '-8' to each side of the equation.
8 + -3.4x + -8 + x2 = 0 + -8

Reorder the terms:
8 + -8 + -3.4x + x2 = 0 + -8

Combine like terms: 8 + -8 = 0
0 + -3.4x + x2 = 0 + -8
-3.4x + x2 = 0 + -8

Combine like terms: 0 + -8 = -8
-3.4x + x2 = -8

The x term is -3.4x.  Take half its coefficient (-1.7).
Square it (2.89) and add it to both sides.

Add '2.89' to each side of the equation.
-3.4x + 2.89 + x2 = -8 + 2.89

Reorder the terms:
2.89 + -3.4x + x2 = -8 + 2.89

Combine like terms: -8 + 2.89 = -5.11
2.89 + -3.4x + x2 = -5.11

Factor a perfect square on the left side:
(x + -1.7)(x + -1.7) = -5.11

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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